Assignment #86 and Letter at a Time

Code

    ///Name: Tim Gibson
    ///Period: 6
    ///Project Name: Letter at a Time
    ///File Name: LetterAtATime.java
    ///Date Finished: 11/3/15
        
    import java.util.Scanner;

    public class LetterAtATime
    {
    	public static void main( String[] args )
    	{
    		Scanner kb = new Scanner(System.in);
    
    		System.out.print("What is your message? ");
    		String message = kb.nextLine();
    
    		System.out.println("\nYour message is " + message.length() + " characters long.");
    		System.out.println("The first character is at position 0 and is '" + message.charAt(0) + "'.");
    		int lastpos = message.length() - 1;
    		System.out.println("The last character is at position " + lastpos + " and is '" + message.charAt(lastpos) + "'.");
    		System.out.println("\nHere are all the characters, one at a time:\n");
    		
    		for ( int i=0; i < message.length(); i++ )
    		{
    			System.out.println("\t" + i + " - '" + message.charAt(i) + "'");
    		}
    
    		int v_count = 0;
    
    		for ( int i=0; i < message.length(); i++ )
    		{
    			char letter = message.charAt(i);
    			if ( letter == 'a' || letter == 'A' || letter == 'e' || letter == 'E' || letter == 'i' || letter == 'I' || letter == 'o' || letter == 'O' || letter == 'u' || letter == 'U')
    			{
    				v_count++;
    			}
    		}
    
    		System.out.println("\nYour message contains vowels " + v_count + " times. Isn't that interesting?");
    
    	}
    }
    //the a counting won't work if it's a <=
    // the length of box is 3. the x is in position 2
    // becaus message length and position are different    
    	
    

Picture of the output